What is the integral of (10)/(sqrt(x))+10sqrt(x) ?

The integral of (10)/(sqrt(x))+10sqrt(x) is 20sqrt(x)+20/3 x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (10)/(sqrt(x))+10sqrt(x)

\int \frac{10}{x} + 10 x d x

20 x + \frac{20}{3} x^{\frac{3}{2}} + C

Solution steps

\int \frac{10}{x} + 10 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{10}{x} d x + \int 10 x d x

\int \frac{10}{x} d x = 20 x

\int 10 x d x = \frac{20}{3} x^{\frac{3}{2}}

= 20 x + \frac{20}{3} x^{\frac{3}{2}}

Add a constant to the solution

= 20 x + \frac{20}{3} x^{\frac{3}{2}} + C

x \to - 2 + lim (\frac{∣ x + 2 ∣}{x + 2})

\int \frac{x + 11}{x ^{2} + 16 x + 68} d x

x \to 1 lim (x^{2} + 3 x)

x \to 1 lim (\frac{x ^{3} - x ^{2} - 4 x + 4}{x ^{3} + 6 x ^{2} + 5 x - 12})

\frac{d}{d x} (2 x^{2} y^{3})

What is the integral of (10)/(sqrt(x))+10sqrt(x) ?
The integral of (10)/(sqrt(x))+10sqrt(x) is 20sqrt(x)+20/3 x^{3/2}+C