What is the limit as x approaches pi-of-ln(1+cos(x)) ?

The limit as x approaches pi-of-ln(1+cos(x)) is infinity

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limit as x approaches pi-of-ln(1+cos(x))

x \to π - lim (- ln (1 + cos (x)))

\infty

Solution steps

x \to π - lim (- ln (1 + cos (x)))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to π - lim (ln (1 + cos (x)))

Apply the Limit Chain Rule:

- \infty

= - (- \infty)

Simplify

= \infty

x \to 0 lim (x^{2} \cdot ln (x^{2}))

x \to \infty lim (- x^{5})

x \to - 2 lim (x + 7)

x \to 3 lim (- x)

x \to - 1 lim (5 x + 4)

What is the limit as x approaches pi-of-ln(1+cos(x)) ?
The limit as x approaches pi-of-ln(1+cos(x)) is infinity