What is the limit as x approaches 8 of (x^2)/(x-8) ?

The limit as x approaches 8 of (x^2)/(x-8) is diverges

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limit as x approaches 8 of (x^2)/(x-8)

x \to 8 lim (\frac{x ^{2}}{x - 8})

diverges

Solution steps

x \to 8 lim (\frac{x ^{2}}{x - 8})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 8 + lim (\frac{x ^{2}}{x - 8}) = \infty

x \to 8 - lim (\frac{x ^{2}}{x - 8}) = - \infty

= diverges

x \to 3 lim (5 f (x))

x \to 0 lim (- 5)

x \to 5 lim (\frac{2 x ^{2} - 11 x + 5}{x - 5})

x \to 0 lim (\frac{4 + x}{x})

x \to - 2 + lim (1 + x^{3})

What is the limit as x approaches 8 of (x^2)/(x-8) ?
The limit as x approaches 8 of (x^2)/(x-8) is diverges