What is the limit as x approaches 0 of (sin(8x)-2)/x ?

The limit as x approaches 0 of (sin(8x)-2)/x is diverges

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limit as x approaches 0 of (sin(8x)-2)/x

x \to 0 lim (\frac{sin ( 8 x ) - 2}{x})

diverges

Solution steps

x \to 0 lim (\frac{sin ( 8 x ) - 2}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{sin ( 8 x ) - 2}{x}) = - \infty

x \to 0 - lim (\frac{sin ( 8 x ) - 2}{x}) = \infty

= diverges

x \to 0 lim (ln (3 x))

x \to 0 lim (f (x) (1 - x^{2}))

x \to 9 lim (x + 3)

x \to - 0 lim (\frac{sin ( 4 x )}{x})

x \to \frac{1}{2} + lim (\frac{4}{2 x - 1})

What is the limit as x approaches 0 of (sin(8x)-2)/x ?
The limit as x approaches 0 of (sin(8x)-2)/x is diverges