What is the derivative of 40(x^2-2x) ?

The derivative of 40(x^2-2x) is 40(2x-2)

What is the first derivative of 40(x^2-2x) ?

The first derivative of 40(x^2-2x) is 40(2x-2)

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\frac{d}{d x} (40 (x^{2} - 2 x))

40 (2 x - 2)

Solution steps

\frac{d}{d x} (40 (x^{2} - 2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 40 \frac{d}{d x} (x^{2} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 40 (\frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

= 40 (2 x - 2)

\int_{2}^{3} \frac{10}{3 - x} d x

\frac{d}{d x} (cos^{- 1} (x))

t^{2}

\int \frac{x + 7}{x} d x

y = x - 1, 1, 2

What is the derivative of 40(x^2-2x) ?
The derivative of 40(x^2-2x) is 40(2x-2)
What is the first derivative of 40(x^2-2x) ?
The first derivative of 40(x^2-2x) is 40(2x-2)