What is the limit as x approaches 0-of (sin(x))/(2x) ?

The limit as x approaches 0-of (sin(x))/(2x) is 1/2

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limit as x approaches 0-of (sin(x))/(2x)

x \to 0 - lim (\frac{sin ( x )}{2 x})

\frac{1}{2}

Decimal

0.5

Solution steps

x \to 0 - lim (\frac{sin ( x )}{2 x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{1}{2} \cdot x \to 0 - lim (\frac{sin ( x )}{x})

Apply L'Hopital's Rule

: x \to 0 - lim (\frac{cos ( x )}{1})

= \frac{1}{2} \cdot x \to 0 - lim (\frac{cos ( x )}{1})

Plug in the value

x = 0

= \frac{1}{2} \cdot \frac{cos ( 0 )}{1}

Simplify

\frac{1}{2} \cdot \frac{cos ( 0 )}{1} : \frac{1}{2}

= \frac{1}{2}

x \to 0 lim (\frac{∣ x ∣}{2 ∣ x ∣})

z \to - 1 lim (30 (4 z - 2)^{3})

x \to \infty lim (x^{3} - 2)

x \to 0 lim (\frac{4}{x ^{3}})

x \to 2 + lim (\frac{2}{2 - x})

What is the limit as x approaches 0-of (sin(x))/(2x) ?
The limit as x approaches 0-of (sin(x))/(2x) is 1/2