What is the solution for xy^'+2y=4e^x ?

The solution for xy^'+2y=4e^x is y=(4(e^xx-e^x))/(x^2)+(c_{1})/(x^2)

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xy^'+2y=4e^x

x y^{^{'}} + 2 y = 4 e^{x}

y = \frac{4 ( e ^{x} x - e ^{x} )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

Solution steps

x y^{'} (x) + 2 y = 4 e^{x}

Solve linear ODE:

y = \frac{4 ( e ^{x} x - e ^{x} )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

y = \frac{4 ( e ^{x} x - e ^{x} )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

\int_{- 1}^{0} (x - 2) d x

x \to - \infty lim (\frac{x + 3 e ^{2 x}}{x + e ^{2 x}})

x, x = 8 - \frac{1}{4} y^{2}

\frac{\partial}{\partial x} (x^{y})

\int - e^{2 x} x d x

What is the solution for xy^'+2y=4e^x ?
The solution for xy^'+2y=4e^x is y=(4(e^xx-e^x))/(x^2)+(c_{1})/(x^2)