What is the limit as x approaches 0 of (1+sin(x))/x ?

The limit as x approaches 0 of (1+sin(x))/x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (1+sin(x))/x

x \to 0 lim (\frac{1 + sin ( x )}{x})

diverges

Solution steps

x \to 0 lim (\frac{1 + sin ( x )}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1 + sin ( x )}{x}) = \infty

x \to 0 - lim (\frac{1 + sin ( x )}{x}) = - \infty

= diverges

x \to 3 lim (∣ x ∣ + ∣ - x ∣)

x \to 0 lim ((x^{2})^{(x^{2})})

x \to 0 lim (\frac{1}{x} - co tan (x))

x \to \infty lim (\frac{9}{10})

x \to - 5 lim (6 x^{2} - 3 x + 2)

What is the limit as x approaches 0 of (1+sin(x))/x ?
The limit as x approaches 0 of (1+sin(x))/x is diverges