What is the solution for y^'=(y^4-3)/(4xy^3) ?

The solution for y^'=(y^4-3)/(4xy^3) is y=\sqrt[4]{c_{1}x+3},y=-\sqrt[4]{c_{1}x+3}

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y^'=(y^4-3)/(4xy^3)

y^{^{'}} = \frac{y ^{4} - 3}{4 x y ^{3}}

Solution steps

y^{'} (x) = \frac{y ^{4} - 3}{4 x y ^{3}}

Solve separable ODE:

f (x) = x^{\frac{3}{5}}

\frac{x ^{2} - a ^{2}}{x - a}

y = x^{6 x}

x \to 0 lim (∣ x ∣^{∣ x ∣})

\int \frac{- x ^{3} + 2 x ^{2} - x + 1}{x ( x ^{2} + 1 ) ^{2}} d x

What is the solution for y^'=(y^4-3)/(4xy^3) ?
The solution for y^'=(y^4-3)/(4xy^3) is y=\sqrt[4]{c_{1}x+3},y=-\sqrt[4]{c_{1}x+3}