What is the limit as n approaches infinity of 1+3/n ?

The limit as n approaches infinity of 1+3/n is 1

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limit as n approaches infinity of 1+3/n

n \to \infty lim (1 + \frac{3}{n})

1

Solution steps

n \to \infty lim (1 + \frac{3}{n})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= n \to \infty lim (1) + n \to \infty lim (\frac{3}{n})

n \to \infty lim (1) = 1

n \to \infty lim (\frac{3}{n}) = 0

= 1 + 0

Simplify

= 1

x \to 0 + lim (x^{2} lo g_{e} (x))

x \to - 1 lim (3 x^{2} - 5)

x \to 0 lim (x ln ∣ 9 x ∣)

x \to 1 lim (\frac{x ^{2} + 1}{x + 2})

x \to 0 + lim (3 x^{s i n (x)})

What is the limit as n approaches infinity of 1+3/n ?
The limit as n approaches infinity of 1+3/n is 1