What is the limit as x approaches 0 of 1/(x^1) ?

The limit as x approaches 0 of 1/(x^1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 1/(x^1)

x \to 0 lim (\frac{1}{x ^{1}})

diverges

Solution steps

x \to 0 lim (\frac{1}{x ^{1}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x ^{1}}) = \infty

x \to 0 - lim (\frac{1}{x ^{1}}) = - \infty

= diverges

x \to 7 lim (1)

x \to 1 - lim (\frac{1}{x ^{2}})

x \to 1 lim (\frac{( e ^{x} )}{x - 1})

x \to 0 lim (\frac{x ^{2} ln ( x )}{2})

x \to 0 lim ((1 - 3 x)^{\frac{5}{x}})

What is the limit as x approaches 0 of 1/(x^1) ?
The limit as x approaches 0 of 1/(x^1) is diverges