en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-infinity of (sqrt(1+16x^6))/(7-x^3)

Solution

x \to - \infty lim (\frac{1 + 16 x ^{6}}{7 - x ^{3}})

Solution

Does not exist

Solution steps

x \to - \infty lim (\frac{1 + 16 x ^{6}}{7 - x ^{3}})

Multiply by the conjugate of

1 + 16 x^{6} : \frac{1 - 256 x ^{12}}{1 - 16 x ^{6}}

= x \to - \infty lim \frac{\frac{1 - 256 x ^{12}}{1 - 16 x ^{6}}}{7 - x ^{3}}

Simplify

\frac{\frac{1 - 256 x ^{12}}{1 - 16 x ^{6}}}{7 - x ^{3}} : \frac{1 - 256 x ^{12}}{( 7 - x ^{3} ) 1 - 16 x ^{6}}

= x \to - \infty lim (\frac{1 - 256 x ^{12}}{( 7 - x ^{3} ) 1 - 16 x ^{6}})

\frac{1 - 256 x ^{12}}{( 7 - x ^{3} ) 1 - 16 x ^{6}}

undefined for

x

approaching

- \infty

= Does not exist

Graph

Popular Examples

limit as x approaches-3 of (6x+5)/(x+8)

x \to - 3 lim (\frac{6 x + 5}{x + 8})

limit as x approaches 1+of x^{8/(x-1)}

x \to 1 + lim (x^{\frac{8}{x - 1}})

limit as x approaches-7-of (|x+7|)/(x+7)

x \to - 7 - lim (\frac{∣ x + 7 ∣}{x + 7})

limit as x approaches 0 of (ln(2x+1))/x

x \to 0 lim (\frac{ln ( 2 x + 1 )}{x})

limit as x approaches infinity of 1/2*x

x \to \infty lim (\frac{1}{2} \cdot x)

Frequently Asked Questions (FAQ)

What is the limit as x approaches-infinity of (sqrt(1+16x^6))/(7-x^3) ?
The limit as x approaches-infinity of (sqrt(1+16x^6))/(7-x^3) is Does not exist