What is the limit as x approaches-1/2 of 7/(|2x+1|) ?

The limit as x approaches-1/2 of 7/(|2x+1|) is infinity

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limit as x approaches-1/2 of 7/(|2x+1|)

x \to - \frac{1}{2} lim (\frac{7}{∣ 2 x + 1 ∣})

\infty

Solution steps

x \to - \frac{1}{2} lim (\frac{7}{∣ 2 x + 1 ∣})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - \frac{1}{2} - lim (\frac{7}{∣ 2 x + 1 ∣}) = \infty

x \to - \frac{1}{2} + lim (\frac{7}{∣ 2 x + 1 ∣}) = \infty

= \infty

x \to 2 lim (5 x - 1)

x \to 0 lim (\frac{e ^{\frac{x}{2}} - 1}{x})

x \to 0 lim (\frac{a ^{x}}{x})

x \to - 1 + lim (x^{2} + 1)

x \to 0 lim (\frac{cos ( x ) + x}{x})

What is the limit as x approaches-1/2 of 7/(|2x+1|) ?
The limit as x approaches-1/2 of 7/(|2x+1|) is infinity