What is the limit as h approaches 0 of (x+1+h-x-1)/h ?

The limit as h approaches 0 of (x+1+h-x-1)/h is 1

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limit as h approaches 0 of (x+1+h-x-1)/h

h \to 0 lim (\frac{x + 1 + h - x - 1}{h})

1

Solution steps

h \to 0 lim (\frac{x + 1 + h - x - 1}{h})

Simplify

= h \to 0 lim (1)

x \to a lim c = c

= 1

x \to 0 + lim (x (ln (x))^{6})

x \to 5 lim (\frac{x ^{2} - 2}{x - 5})

x \to - 2 lim (\frac{1}{( x + 2 )})

x \to - 3 lim (\frac{1}{( x + 3 ) ^{4}})

x \to 0 lim (+ \frac{ln ( x )}{x})

What is the limit as h approaches 0 of (x+1+h-x-1)/h ?
The limit as h approaches 0 of (x+1+h-x-1)/h is 1