What is the integral of sqrt(x+4) ?

The integral of sqrt(x+4) is 2/3 (x+4)^{3/2}+C

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integral of sqrt(x+4)

\int x + 4 d x

\frac{2}{3} (x + 4)^{\frac{3}{2}} + C

Solution steps

\int x + 4 d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = x + 4

= \frac{2}{3} (x + 4)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} (x + 4)^{\frac{3}{2}} + C

x \to 1 lim (tan (\frac{π x}{2}))

y^{^{'}} = \frac{( x y )}{2}

x \to 1 + lim (\frac{1}{x - 1} - \frac{1}{ln ( x )})

\int \frac{( e ^{6 x} )}{e ^{6 x} + 1} d x

y = x, y = 2 x 64 - x^{2}

What is the integral of sqrt(x+4) ?
The integral of sqrt(x+4) is 2/3 (x+4)^{3/2}+C