What is the limit as x approaches 0 of 2x^2-ln(x) ?

The limit as x approaches 0 of 2x^2-ln(x) is Does not exist

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limit as x approaches 0 of 2x^2-ln(x)

x \to 0 lim (2 x^{2} - ln (x))

Does not exist

Solution steps

x \to 0 lim (2 x^{2} - ln (x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (2 x^{2} - ln (x)) = \infty

x \to 0 - lim (2 x^{2} - ln (x)) =

Does not exist

= Does not exist

x \to 3 lim (4 x^{2} - 5 x + 4)

x \to 0 lim (\frac{sin ( 2 x )}{2})

n \to \infty lim (\frac{2}{n} + \frac{3}{3 n})

x \to 1 - lim (\frac{ln ( x )}{x - 1})

x \to 0 + lim (\frac{cos ^{2} ( x )}{x})

What is the limit as x approaches 0 of 2x^2-ln(x) ?
The limit as x approaches 0 of 2x^2-ln(x) is Does not exist