What is the tangent of f(x)=2-7x^2,\at x=4 ?

The tangent of f(x)=2-7x^2,\at x=4 is y=-56x+114

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=2-7x^2,\at x=4

tangent of

f (x) = 2 - 7 x^{2}, at x = 4

y = - 56 x + 114

Solution steps

Find the tangent point:

(4, - 110)

Find the slope of

f (x) = 2 - 7 x^{2} : \frac{df ( x )}{d x} = - 14 x

Compute the slope of

f (x) = 2 - 7 x^{2}

x = 4 : m = - 56

Find the line with slope m=

- 56

and passing through

(4, - 110) : y = - 56 x + 114

y = - 56 x + 114

\frac{d}{d x} (e^{x} \cdot cos (y))

\int y e^{y} d y

x \to \infty lim (5 x + 4)

\frac{\partial}{\partial x} (x sin (7 x^{2} y))

x \to 0 lim (\frac{x ^{2} + 1}{x})

What is the tangent of f(x)=2-7x^2,\at x=4 ?
The tangent of f(x)=2-7x^2,\at x=4 is y=-56x+114