What is the limit as x approaches 0 of (x+e^x) 1/x ?

The limit as x approaches 0 of (x+e^x) 1/x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (x+e^x) 1/x

x \to 0 lim ((x + e^{x}) \frac{1}{x})

diverges

Solution steps

x \to 0 lim ((x + e^{x}) \frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((x + e^{x}) \frac{1}{x}) = \infty

x \to 0 - lim ((x + e^{x}) \frac{1}{x}) = - \infty

= diverges

x \to - 1 lim (\frac{1 - x}{1 + x})

x \to 58 - lim (ln (x) + 2)

x \to 0 lim (\frac{sinh ( x )}{h})

x \to \infty lim (- ln (5 x))

x \to π + lim (\frac{3}{sin ( x )})

What is the limit as x approaches 0 of (x+e^x) 1/x ?
The limit as x approaches 0 of (x+e^x) 1/x is diverges