What is the slope of 4x^2+16y^2-51 ?

The slope of 4x^2+16y^2-51 is (8x)/(1-32y)

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slope of 4x^2+16y^2-51

slope

4 x^{2} + 16 y^{2} - 51

\frac{8 x}{1 - 32 y}

Solution steps

y = 4 x^{2} + 16 y^{2} - 51

Use implicit differentiation to find the slope of

y = 4 x^{2} + 16 y^{2} - 51

Implicit Derivative

\frac{d y}{d x}

y = 4 x^{2} + 16 y^{2} - 51 : \frac{8 x}{1 - 32 y}

\frac{8 x}{1 - 32 y}

\frac{\partial}{\partial x} (ln e^{1 + x^{2}} + 3 x^{4} + cot^{2} (π x))

x \to - 2 lim (x^{2} + 3 x - 1)

\int 2 \cdot sin (x) \cdot cos (x) d x

\frac{d}{d x} (I n (x^{2} y))

\frac{( x ^{2} + 1 ) d y}{d x} + x y - x = 0