What is volumeabout x=-1,x=y^3,[0,1] ?

The answer to volumeabout x=-1,x=y^3,[0,1] is (23pi)/(14)

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volumeabout x=-1,x=y^3,[0,1]

volume about

x = - 1, x = y^{3}, [0, 1]

\frac{23 π}{14}

Decimal Notation

5.16118 \dots

Solution steps

Apply the volume formula:

\int_{0}^{1} π (y^{3} + 1)^{2} d y

Solve

\int_{0}^{1} π (y^{3} + 1)^{2} d y : \frac{23 π}{14}

The volume for solid of revolution is:

= \frac{23 π}{14}

\frac{d}{d x} (8 + cot^{2} (x))

x \to 2 lim (3 x^{3} + x^{2} - 8)

f (x) = 6 x^{9} e^{x}

p x + d

\frac{d}{d x} (4 x ln (x) + 10)

What is volumeabout x=-1,x=y^3,[0,1] ?
The answer to volumeabout x=-1,x=y^3,[0,1] is (23pi)/(14)