What is the derivative of 4x^2-x+sqrt(x) ?

The derivative of 4x^2-x+sqrt(x) is 8x-1+1/(2sqrt(x))

What is the first derivative of 4x^2-x+sqrt(x) ?

The first derivative of 4x^2-x+sqrt(x) is 8x-1+1/(2sqrt(x))

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\frac{d}{d x} (4 x^{2} - x + x)

8 x - 1 + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (4 x^{2} - x + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d x}{d x} = 1

\frac{d}{d x} (x) = \frac{1}{2 x}

= 8 x - 1 + \frac{1}{2 x}

e^{x} + \frac{1}{1 + x}

\frac{d}{d t} (ln (sec (t)))

\frac{d ^{2}}{d x ^{2}} (x^{2} cos (x))

\int \frac{x}{( 3 x ^{2} - 1 )} d x

\int_{1}^{5} \frac{1}{x - 2} d x

What is the derivative of 4x^2-x+sqrt(x) ?
The derivative of 4x^2-x+sqrt(x) is 8x-1+1/(2sqrt(x))
What is the first derivative of 4x^2-x+sqrt(x) ?
The first derivative of 4x^2-x+sqrt(x) is 8x-1+1/(2sqrt(x))