What is the limit as x approaches 4 of (3-x)/(x^2-9) ?

The limit as x approaches 4 of (3-x)/(x^2-9) is -1/7

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limit as x approaches 4 of (3-x)/(x^2-9)

x \to 4 lim (\frac{3 - x}{x ^{2} - 9})

- \frac{1}{7}

Decimal

- 0.14285 \dots

Solution steps

x \to 4 lim (\frac{3 - x}{x ^{2} - 9})

Plug in the value

x = 4

= \frac{3 - 4}{4 ^{2} - 9}

Simplify

= - \frac{1}{7}

x \to - 2 lim (\frac{( 8 x ^{3} - 16 x ^{2} - 64 x )}{x ^{2} + 2 x})

x \to \infty lim (10 x (ln (x + 8) - ln (x)))

x \to 0 lim (\frac{5}{x} - \frac{5}{e ^{t} - 1})

x \to 0 lim (\frac{( x - tan ( 3 x ) )}{( x + tan ( 2 x ) )})

x \to - 5 lim (\frac{25 - x ^{2}}{5 + x})

What is the limit as x approaches 4 of (3-x)/(x^2-9) ?
The limit as x approaches 4 of (3-x)/(x^2-9) is -1/7