What is the limit as x approaches 0 of-(2^{1/x}) ?

The limit as x approaches 0 of-(2^{1/x}) is diverges

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limit as x approaches 0 of-(2^{1/x})

x \to 0 lim (- (2^{\frac{1}{x}}))

diverges

Solution steps

x \to 0 lim (- 2^{\frac{1}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (- 2^{\frac{1}{x}}) = - \infty

x \to 0 - lim (- 2^{\frac{1}{x}}) = 0

= diverges

x \to 3 lim (\frac{4 - x ^{2}}{x + 3})

x \to 6 lim (\frac{x ^{2} - 4}{x - 6})

h \to 0 lim (\frac{( h - 2 ) ^{3} + 8}{h})

t \to 1 lim (sin (2 t))

x \to 0 lim (∣ x ∣ + 1)

What is the limit as x approaches 0 of-(2^{1/x}) ?
The limit as x approaches 0 of-(2^{1/x}) is diverges