What is the integral from 0 to pi of 2sin(x) ?

The integral from 0 to pi of 2sin(x) is 4

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integral from 0 to pi of 2sin(x)

\int_{0}^{π} 2 sin (x) d x

4

Solution steps

\int_{0}^{π} 2 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 2 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 2 \cdot 2

Simplify

= 4

\frac{d}{d θ} (- 8 sin (θ))

\frac{2}{s + 10.04}

x \to - \infty lim (3 - 4 x^{2})

x \to \infty lim (\frac{x ^{3}}{2 ^{x}})

\int sin (- 2 x) d x

What is the integral from 0 to pi of 2sin(x) ?
The integral from 0 to pi of 2sin(x) is 4