What is the limit as x approaches 1 of ln(x^2-3x+2) ?

The limit as x approaches 1 of ln(x^2-3x+2) is Does not exist

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limit as x approaches 1 of ln(x^2-3x+2)

x \to 1 lim (ln (x^{2} - 3 x + 2))

Does not exist

Solution steps

x \to 1 lim (ln (x^{2} - 3 x + 2))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (ln (x^{2} - 3 x + 2)) =

Does not exist

x \to 1 - lim (ln (x^{2} - 3 x + 2)) = - \infty

= Does not exist

x \to - 4 lim (3 x^{2} + 12 x)

x \to 1 lim (\frac{x ^{3} - 3 x}{x})

x \to 0 lim (x^{1} sin (\frac{1}{x}))

x \to 1 lim (\frac{x ^{4} + x ^{2} - 2}{x ^{2} + 2 x - 3})

x \to 0 lim (\frac{ln ( 1 + x ^{2} )}{2 x ^{2}})

What is the limit as x approaches 1 of ln(x^2-3x+2) ?
The limit as x approaches 1 of ln(x^2-3x+2) is Does not exist