What is the integral of (9x^5-3x^2+7) ?

The integral of (9x^5-3x^2+7) is (3x^6)/2-x^3+7x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (9x^5-3x^2+7)

\int (9 x^{5} - 3 x^{2} + 7) d x

\frac{3 x ^{6}}{2} - x^{3} + 7 x + C

Solution steps

\int 9 x^{5} - 3 x^{2} + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x^{5} d x - \int 3 x^{2} d x + \int 7 d x

\int 9 x^{5} d x = \frac{3 x ^{6}}{2}

\int 3 x^{2} d x = x^{3}

\int 7 d x = 7 x

= \frac{3 x ^{6}}{2} - x^{3} + 7 x

Add a constant to the solution

= \frac{3 x ^{6}}{2} - x^{3} + 7 x + C

\frac{d ^{2}}{d x ^{2}} (x ln (x))

\int (\frac{x}{x + 1}) d x

\int tan^{3} (3 x) sec (3 x) d x

\int \frac{1}{( k - 1 ) ^{4}}

y = \frac{3 x ^{2} + 2}{x + 1}

What is the integral of (9x^5-3x^2+7) ?
The integral of (9x^5-3x^2+7) is (3x^6)/2-x^3+7x+C