What is the limit as x approaches 0-of 3e^{-9/x} ?

The limit as x approaches 0-of 3e^{-9/x} is infinity

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limit as x approaches 0-of 3e^{-9/x}

x \to 0 - lim (3 e^{- \frac{9}{x}})

\infty

Solution steps

x \to 0 - lim (3 e^{- \frac{9}{x}})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 3 \cdot x \to 0 - lim (e^{- \frac{9}{x}})

Apply the Limit Chain Rule:

\infty

= 3 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

x \to 0 lim (1 x^{2})

x \to 4 + lim (2 + x - 4)

x \to 8 lim (7 - \frac{1}{2} x)

x \to 0 lim ((1 - x)^{2})

x \to - \frac{1}{2} lim (\frac{2 x ^{2} + 7 x + 3}{2 x ^{2} + 3 x + 1})

What is the limit as x approaches 0-of 3e^{-9/x} ?
The limit as x approaches 0-of 3e^{-9/x} is infinity