What is the limit as x approaches 0 of x^3ln(4x) ?

The limit as x approaches 0 of x^3ln(4x) is Does not exist

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limit as x approaches 0 of x^3ln(4x)

x \to 0 lim (x^{3} ln (4 x))

Does not exist

Solution steps

x \to 0 lim (x^{3} ln (4 x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x^{3} ln (4 x)) = 0

x \to 0 - lim (x^{3} ln (4 x)) =

Does not exist

= Does not exist

x \to 2 lim (x ln (\frac{x}{x - 2}))

x \to - 2 lim ((\frac{1}{2})^{x})

h \to 0 lim (h - 2)

h \to 0 lim (\frac{1 + h - 1}{h})

x \to 0 lim (\frac{x}{x ^{3} - 1})

What is the limit as x approaches 0 of x^3ln(4x) ?
The limit as x approaches 0 of x^3ln(4x) is Does not exist