What is (\partial)/(\partial x)(cos(x)+sin(y)) ?

The answer to (\partial)/(\partial x)(cos(x)+sin(y)) is -sin(x)

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(\partial)/(\partial x)(cos(x)+sin(y))

\frac{\partial}{\partial x} (cos (x) + sin (y))

- sin (x)

Solution steps

\frac{\partial}{\partial x} (cos (x) + sin (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (cos (x)) + \frac{\partial}{\partial x} (sin (y))

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

\frac{\partial}{\partial x} (sin (y)) = 0

= - sin (x) + 0

Simplify

= - sin (x)

\int x^{6} ln (2 x) d x

\frac{d y}{d t} = 3 y + y^{6}

f (x) = \frac{2 - x e ^{x}}{x + e ^{x}}

e^{x} \cdot cos (x)

\int_{- 1}^{1} (\frac{1}{1 + x ^{2}})^{2} d x

What is (\partial)/(\partial x)(cos(x)+sin(y)) ?
The answer to (\partial)/(\partial x)(cos(x)+sin(y)) is -sin(x)