What is the limit as x approaches-1-of (|x+1|)/(2x+2) ?

The limit as x approaches-1-of (|x+1|)/(2x+2) is -1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-1-of (|x+1|)/(2x+2)

x \to - 1 - lim (\frac{∣ x + 1 ∣}{2 x + 2})

- \frac{1}{2}

Decimal

- 0.5

Solution steps

x \to - 1 - lim (\frac{∣ x + 1 ∣}{2 x + 2})

x + 1

is negative when

x \to - 1 -

. Therefore

∣ x + 1 ∣ = - x - 1

= x \to - 1 - lim (\frac{- x - 1}{2 x + 2})

\frac{- x - 1}{2 x + 2} = - \frac{1}{2}

= x \to - 1 - lim (- \frac{1}{2})

x \to a lim c = c

= - \frac{1}{2}

x \to - 1 lim (2 x^{2} - 5 x + 3 x)

x \to π lim (\frac{sin ( x )}{tan ( x )})

x \to \infty lim (x, 0)

x \to \infty lim (xxxx)

x \to \infty lim (- 6 + \frac{1}{x})

What is the limit as x approaches-1-of (|x+1|)/(2x+2) ?
The limit as x approaches-1-of (|x+1|)/(2x+2) is -1/2