What is the solution for (dy)/(dx)=e^{2x}-3y,y(0)=2 ?

The solution for (dy)/(dx)=e^{2x}-3y,y(0)=2 is y=(e^{2x})/5+9/(5e^{3x)}

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(dy)/(dx)=e^{2x}-3y,y(0)=2

\frac{d y}{d x} = e^{2 x} - 3 y, y (0) = 2

y = \frac{e ^{2 x}}{5} + \frac{9}{5 e ^{3 x}}

Solution steps

\frac{d y}{d x} = e^{2 x} - 3 y

Solve linear ODE:

y = \frac{e ^{2 x}}{5} + \frac{9}{5 e ^{3 x}}

y = \frac{e ^{2 x}}{5} + \frac{9}{5 e ^{3 x}}

\frac{\partial}{\partial x} (x^{5} + y^{3})

y^{^{''}} + 2 y^{^{'}} + y = 16 e^{- t}

2 x + 1

\int_{- 2}^{3} \frac{37}{x ^{4}} d x

x \to 0 lim (\frac{20 sin ( 3 x )}{x})

What is the solution for (dy)/(dx)=e^{2x}-3y,y(0)=2 ?
The solution for (dy)/(dx)=e^{2x}-3y,y(0)=2 is y=(e^{2x})/5+9/(5e^{3x)}