What is the limit as x approaches-3 of (x+1)/(x^2-9) ?

The limit as x approaches-3 of (x+1)/(x^2-9) is diverges

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limit as x approaches-3 of (x+1)/(x^2-9)

x \to - 3 lim (\frac{x + 1}{x ^{2} - 9})

diverges

Solution steps

x \to - 3 lim (\frac{x + 1}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 3 + lim (\frac{x + 1}{x ^{2} - 9}) = \infty

x \to - 3 - lim (\frac{x + 1}{x ^{2} - 9}) = - \infty

= diverges

x \to 0 lim (cos (x))

x \to \frac{π}{3} lim \frac{( sin ( x ) - \frac{3}{2} )}{x - \frac{π}{3}}

x \to \infty lim (\frac{x ^{3}}{x + 4})

x \to - 1 lim (3 \frac{( x ^{2} + 1 ) ( 2 x + 1 )}{3 x + 1})

x \to 0 lim (\frac{sin ( x )}{- 2 tan ( x ) sec ^{2} ( x )})

What is the limit as x approaches-3 of (x+1)/(x^2-9) ?
The limit as x approaches-3 of (x+1)/(x^2-9) is diverges