What is the integral from 2 to 9 of (x^3-pix^2) ?

The integral from 2 to 9 of (x^3-pix^2) is 6545/4-(721pi)/3

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integral from 2 to 9 of (x^3-pix^2)

\int_{2}^{9} (x^{3} - π x^{2}) d x

\frac{6545}{4} - \frac{721 π}{3}

Decimal Notation

881.22056 \dots

Solution steps

\int_{2}^{9} x^{3} - π x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{9} x^{3} d x - \int_{2}^{9} π x^{2} d x

\int_{2}^{9} x^{3} d x = \frac{6545}{4}

\int_{2}^{9} π x^{2} d x = \frac{721 π}{3}

= \frac{6545}{4} - \frac{721 π}{3}

f (x) = 8 (e^{x} + e^{x} x), at x = 0

x^{2} y^{^{'}} + 3 x y = \frac{sin ( 2 x )}{x}

\int \frac{x ^{2} + 25}{9 x ^{2}} d x

x \to 1 + lim (\frac{x + 5}{x + 2})

\frac{\partial}{\partial x} (ln (4 y))

What is the integral from 2 to 9 of (x^3-pix^2) ?
The integral from 2 to 9 of (x^3-pix^2) is 6545/4-(721pi)/3