What is the limit as x approaches 0 of 5/(3+e^{1/x)} ?

The limit as x approaches 0 of 5/(3+e^{1/x)} is diverges

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limit as x approaches 0 of 5/(3+e^{1/x)}

x \to 0 lim (\frac{5}{3 + e ^{\frac{1}{x}}})

diverges

Solution steps

x \to 0 lim (\frac{5}{3 + e ^{\frac{1}{x}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{5}{3 + e ^{\frac{1}{x}}}) = 0

x \to 0 - lim (\frac{5}{3 + e ^{\frac{1}{x}}}) = \frac{5}{3}

= diverges

x \to - 1 lim (x^{2} - 5 x + 17)

x \to 0 lim (x + \frac{2}{x})

x \to 2 lim (\frac{x ^{2} - 4 x + 4}{2 x ^{3} - 3 x ^{2} - 2 x})

x \to - \infty lim (x^{3} + 1)

x \to \infty lim (ln (\frac{x + \frac{1}{x ^{2}}}{1 + \frac{2}{x ^{2}}}))

What is the limit as x approaches 0 of 5/(3+e^{1/x)} ?
The limit as x approaches 0 of 5/(3+e^{1/x)} is diverges