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Popular >

area sqrt(x),x-2,[0,4]

Solution

area

x, x - 2, [0, 4]

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} x - (x - 2) d x

Solve

\int_{0}^{4} x - (x - 2) d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Popular Examples

(d^3)/(dx^3)(3t^3-2/(t^2))

\frac{d ^{3}}{d x ^{3}} (3 t^{3} - \frac{2}{t ^{2}})

integral of (x^3+x+1/(x^3))

\int (x^{3} + x + \frac{1}{x ^{3}}) d x

integral from 0 to pi/2 of-10sin^2(3x)

\int_{0}^{\frac{π}{2}} - 10 sin^{2} (3 x) d x

integral of x/((sqrt(1+2x)))

\int \frac{x}{( 1 + 2 x )} d x

derivative of tan(6x^2)

\frac{d}{d x} (tan (6 x^{2}))

Frequently Asked Questions (FAQ)

What is area sqrt(x),x-2,[0,4] ?
The answer to area sqrt(x),x-2,[0,4] is 16/3