What is the limit as x approaches-pi/2-of 7sin(x)+9 ?

The limit as x approaches-pi/2-of 7sin(x)+9 is 2

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limit as x approaches-pi/2-of 7sin(x)+9

x \to - \frac{π}{2} - lim (7 sin (x) + 9)

2

Solution steps

x \to - \frac{π}{2} - lim (7 sin (x) + 9)

Plug in the value

x = - \frac{π}{2}

= 7 sin (- \frac{π}{2}) + 9

Simplify

7 sin (- \frac{π}{2}) + 9 : 2

= 2

x \to 3 + lim (\frac{x}{( x - 3 ) ^{2}})

x \to 3 + lim (\frac{- 2}{3 - x})

x \to 0 + lim (x^{x + 1})

x \to \infty lim (- 3 x^{5})

x \to - 2 - lim (\frac{x + 4}{x ^{2} - 4})

What is the limit as x approaches-pi/2-of 7sin(x)+9 ?
The limit as x approaches-pi/2-of 7sin(x)+9 is 2