What is the integral from-infinity to 0 of 1/(2-6x) ?

The integral from-infinity to 0 of 1/(2-6x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 0 of 1/(2-6x)

\int_{- \infty}^{0} \frac{1}{2 - 6 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{2 - 6 x} d x

Compute the indefinite integral:

\int \frac{1}{2 - 6 x} d x = - \frac{1}{6} ln ∣ 2 - 6 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{2 - 6 x} d x =

diverges

= diverges

\frac{\partial}{\partial y} (3.5 x y cos (x yz))

\int \frac{1}{9 x ^{2} - 1} d x

\int 12 x^{2} + 2 x - 6 d x

\int 9 arctan (x) d x

\frac{\partial}{\partial y} (7 y - 5 x)

What is the integral from-infinity to 0 of 1/(2-6x) ?
The integral from-infinity to 0 of 1/(2-6x) is diverges