What is the limit as x approaches+0 of x*ln(2x) ?

The limit as x approaches+0 of x*ln(2x) is Does not exist

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limit as x approaches+0 of x*ln(2x)

x \to + 0 lim (x \cdot ln (2 x))

Does not exist

Solution steps

x \to 0 lim (x ln (2 x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x ln (2 x)) = 0

x \to 0 - lim (x ln (2 x)) =

Does not exist

= Does not exist

x \to \infty lim \frac{( x + 1 ) ^{2} + 1}{x ^{2} + 1}

x \to 1 lim (\frac{10 - x - 8 + x}{x ^{3} - 1})

x \to - 3 + lim (- \frac{sin ( c - 3 x )}{e ^{5 x + 15} - 1})

x \to 0 + lim (\frac{e ^{x} - 1 - x}{x ^{2}})

x \to \infty lim (\frac{6 x ^{6} + x}{7 x ^{5} - 2 x})

What is the limit as x approaches+0 of x*ln(2x) ?
The limit as x approaches+0 of x*ln(2x) is Does not exist