What is the limit as x approaches-infinity of-2^x-7 ?

The limit as x approaches-infinity of-2^x-7 is -7

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limit as x approaches-infinity of-2^x-7

x \to - \infty lim (- 2^{x} - 7)

- 7

Solution steps

x \to - \infty lim (- 2^{x} - 7)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= - x \to - \infty lim (2^{x}) - x \to - \infty lim (7)

x \to - \infty lim (2^{x}) = 0

x \to - \infty lim (7) = 7

= - 0 - 7

Simplify

= - 7

x \to 0 lim (\frac{3 x ^{2}}{1 + x sin ( x ) - cos ( x )})

x \to \infty lim (x \frac{x}{x + 1})

x \to \infty lim (\frac{e ^{x}}{ln ( x ) + 2})

x \to 0 lim (\frac{- x - ln ( 1 - x )}{8 x ^{2}})

x \to 1 lim (\frac{x + 1}{2 x - 1})

What is the limit as x approaches-infinity of-2^x-7 ?
The limit as x approaches-infinity of-2^x-7 is -7