What is the limit as y approaches 0 of (cos(8y)) 1/(y^2) ?

The limit as y approaches 0 of (cos(8y)) 1/(y^2) is infinity

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limit as y approaches 0 of (cos(8y)) 1/(y^2)

y \to 0 lim ((cos (8 y)) \frac{1}{y ^{2}})

\infty

Solution steps

y \to 0 lim (cos (8 y) \frac{1}{y ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

y \to 0 - lim (cos (8 y) \frac{1}{y ^{2}}) = \infty

y \to 0 + lim (cos (8 y) \frac{1}{y ^{2}}) = \infty

= \infty

x \to 0 lim (x \cdot co tan (x))

x \to 0 lim (x (5^{\frac{1}{x}} - 1))

x \to - 6 lim (\frac{x ^{2} + 15 x + 54}{- 54 - 3 x + x ^{2}})

x \to 0 - lim (\frac{2}{sin ( x )})

x \to - d lim (2 x^{3} + 3 x - 1)

What is the limit as y approaches 0 of (cos(8y)) 1/(y^2) ?
The limit as y approaches 0 of (cos(8y)) 1/(y^2) is infinity