What is the limit as x approaches 1 of 4arcsin(x) ?

The limit as x approaches 1 of 4arcsin(x) is 2pi

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limit as x approaches 1 of 4arcsin(x)

x \to 1 lim (4 arcsin (x))

2 π

Decimal

6.28318 \dots

Solution steps

x \to 1 lim (4 arcsin (x))

Plug in the value

x = 1

= 4 arcsin (1)

Simplify

4 arcsin (1) : 2 π

= 2 π

θ \to 0 lim (sin (θ) cot (2 θ))

x \to 0 + lim (tan (9 x))

x \to 0 + lim (\frac{ln ( x ) sin ( x )}{ln ( x ) tan ( x )})

x \to 1 lim (\frac{9 x ^{8}}{5 x ^{4}})

x \to \infty lim (\frac{sin ( x )}{x ^{4}})

What is the limit as x approaches 1 of 4arcsin(x) ?
The limit as x approaches 1 of 4arcsin(x) is 2pi