What is area y=4(x+1),y=5(x+1),x=2 ?

The answer to area y=4(x+1),y=5(x+1),x=2 is 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=4(x+1),y=5(x+1),x=2

area

y = 4 (x + 1), y = 5 (x + 1), x = 2

\frac{9}{2}

Decimal Notation

4.5

Solution steps

Apply the area formula:

\int_{- 1}^{2} ∣ x + 1 ∣ d x

Solve

\int_{- 1}^{2} ∣ x + 1 ∣ d x : \frac{9}{2}

The area is:

= \frac{9}{2}

\frac{d}{d x} (3 x^{2} y^{2})

\frac{d}{d x} (x (1 - x^{2})^{\frac{1}{2}})

n = 0 \sum \infty i (- 1)^{n}

(x + x) \frac{d y}{d x} = y + y

\frac{d}{d x} (4 arccos (1 - x^{2}))

What is area y=4(x+1),y=5(x+1),x=2 ?
The answer to area y=4(x+1),y=5(x+1),x=2 is 9/2