What is the limit as x approaches 0 of ln(1-x^2) ?

The limit as x approaches 0 of ln(1-x^2) is 0

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limit as x approaches 0 of ln(1-x^2)

x \to 0 lim (ln (1 - x^{2}))

0

Solution steps

x \to 0 lim (ln (1 - x^{2}))

Plug in the value

x = 0

= ln (1 - 0^{2})

Simplify

ln (1 - 0^{2}) : 0

= 0

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x \to 1 lim ((2 - x)^{7 t a n (\frac{π}{2} x)})

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x \to \infty lim (x^{11})

x \to 0 lim (\frac{x}{n 1 + a x k 1 + b x - 1})

What is the limit as x approaches 0 of ln(1-x^2) ?
The limit as x approaches 0 of ln(1-x^2) is 0