What is the derivative of 1-x^4 ?

The derivative of 1-x^4 is -4x^3

What is the first derivative of 1-x^4 ?

The first derivative of 1-x^4 is -4x^3

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\frac{d}{d x} (1 - x^{4})

- 4 x^{3}

Solution steps

\frac{d}{d x} (1 - x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (x^{4})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{4}) = 4 x^{3}

= 0 - 4 x^{3}

Simplify

= - 4 x^{3}

6 y^{^{''}} + y^{^{'}} - 2 y = 0

\frac{d ^{2}}{d x ^{2}} (e^{- k x^{2}})

\int 2 x 9 - x^{2} d x

x y^{^{'}} = y + 2 x^{2} y, y (1) = 1

g (x) = 5 tan (3 x)