What is the limit as t approaches 0 of 2/t-1/(e^t-1) ?

The limit as t approaches 0 of 2/t-1/(e^t-1) is diverges

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limit as t approaches 0 of 2/t-1/(e^t-1)

t \to 0 lim (\frac{2}{t} - \frac{1}{e ^{t} - 1})

diverges

Solution steps

t \to 0 lim (\frac{2}{t} - \frac{1}{e ^{t} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

t \to 0 + lim (\frac{2}{t} - \frac{1}{e ^{t} - 1}) = \infty

t \to 0 - lim (\frac{2}{t} - \frac{1}{e ^{t} - 1}) = - \infty

= diverges

x \to 0 lim (\frac{- 2 x ^{2}}{x ^{2}})

x \to 0 lim (+ (\frac{sin ( x )}{x}))

x \to \infty lim (x i)

x \to 4 lim (e^{x} + 3)

x \to - 2 lim (\frac{( x + 2 )}{x - 2})

What is the limit as t approaches 0 of 2/t-1/(e^t-1) ?
The limit as t approaches 0 of 2/t-1/(e^t-1) is diverges