What is the limit as x approaches-1 of (2x+2)(x+2) ?

The limit as x approaches-1 of (2x+2)(x+2) is 0

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limit as x approaches-1 of (2x+2)(x+2)

x \to - 1 lim ((2 x + 2) (x + 2))

0

Solution steps

x \to - 1 lim ((2 x + 2) (x + 2))

Plug in the value

x = - 1

= (2 (- 1) + 2) (- 1 + 2)

Simplify

(2 (- 1) + 2) (- 1 + 2) : 0

= 0

x \to \infty lim (3^{x} x!)

x \to 1 lim (e^{\frac{1}{x ^{2} - 1}})

x \to - 1 lim (\frac{e ^{x^{2}} - 1}{x})

x \to - 2 lim (x - x^{2})

x \to 0 lim (\frac{x ^{4}}{1 + x ^{5}})

What is the limit as x approaches-1 of (2x+2)(x+2) ?
The limit as x approaches-1 of (2x+2)(x+2) is 0