What is the first derivative of 3x^2-9 ?

The first derivative of 3x^2-9 is 6x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of 3x^2-9

\frac{d}{d x} (3 x^{2} - 9)

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (9)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (9) = 0

= 6 x - 0

Simplify

= 6 x

n = 0 \sum \infty \frac{4 ^{n}}{5 ^{n}}

f (x) = (3 x + 70)^{50}

6 x^{\frac{3}{2}}

y^{^{''}} + 6.2832 y = 0

n = 0 \sum \infty (\frac{4}{5})^{n}