What is the limit as x approaches 1 of ln(1/(x-1)) ?

The limit as x approaches 1 of ln(1/(x-1)) is Does not exist

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limit as x approaches 1 of ln(1/(x-1))

x \to 1 lim (ln (\frac{1}{x - 1}))

Does not exist

Solution steps

x \to 1 lim (ln (\frac{1}{x - 1}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (ln (\frac{1}{x - 1})) = \infty

x \to 1 - lim (ln (\frac{1}{x - 1})) =

Does not exist

= Does not exist

x \to - 1 lim (3 x^{3} - 4 x + 8)

x \to 3 lim (\frac{x - 5}{x ^{2} - 9})

x \to 0 + lim (\frac{1}{x} sin (\frac{x}{2}))

x \to 2 lim (\frac{2 x - 1}{x - 2})

x \to 0 lim (\frac{- sin ( 5 x )}{x})

What is the limit as x approaches 1 of ln(1/(x-1)) ?
The limit as x approaches 1 of ln(1/(x-1)) is Does not exist