What is the derivative of (x^3/3-1/(4x)) ?

The derivative of (x^3/3-1/(4x)) is x^2+1/(4x^2)

What is the first derivative of (x^3/3-1/(4x)) ?

The first derivative of (x^3/3-1/(4x)) is x^2+1/(4x^2)

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Popular >

\frac{d}{d x} (\frac{x ^{3}}{3} - \frac{1}{4 x})

x^{2} + \frac{1}{4 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} - \frac{1}{4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) - \frac{d}{d x} (\frac{1}{4 x})

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (\frac{1}{4 x}) = - \frac{1}{4 x ^{2}}

= x^{2} - (- \frac{1}{4 x ^{2}})

Simplify

= x^{2} + \frac{1}{4 x ^{2}}

\frac{d}{d x} (\frac{2}{x ^{2} + 7})

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\int_{3}^{6} \frac{x}{x ^{2} + 4 x + 20} d x

\int 8 x^{9} - 3 x^{6} + 12 x^{3} d x

What is the derivative of (x^3/3-1/(4x)) ?
The derivative of (x^3/3-1/(4x)) is x^2+1/(4x^2)
What is the first derivative of (x^3/3-1/(4x)) ?
The first derivative of (x^3/3-1/(4x)) is x^2+1/(4x^2)