What is the limit as x approaches 0+of 2-(96)/(x^3) ?

The limit as x approaches 0+of 2-(96)/(x^3) is -infinity

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limit as x approaches 0+of 2-(96)/(x^3)

x \to 0 + lim (2 - \frac{96}{x ^{3}})

- \infty

Solution steps

x \to 0 + lim (2 - \frac{96}{x ^{3}})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (2) - x \to 0 + lim (\frac{96}{x ^{3}})

x \to 0 + lim (2) = 2

x \to 0 + lim (\frac{96}{x ^{3}}) = \infty

= 2 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

x \to 3 lim (- 2 x + 5)

t \to - 3 lim (\frac{6 t + 5}{t + 8})

x \to 0 lim (e^{3})

x \to 1 lim (\frac{x + 9}{3})

x \to 1 + lim (\frac{x}{x ^{2} + 1})

What is the limit as x approaches 0+of 2-(96)/(x^3) ?
The limit as x approaches 0+of 2-(96)/(x^3) is -infinity